It is a sweltering summer day, and a boy wants to buy some ice cream bars.

At the store, there are n ice cream bars. You are given an array costs of length n, where costs[i] is the price of the ith ice cream bar in coins. The boy initially has coins coins to spend, and he wants to buy as many ice cream bars as possible.

Return the maximum number of ice cream bars the boy can buy with coins coins.

Note: The boy can buy the ice cream bars in any order.

Input: costs = [1,3,2,4,1], coins = 7
Output: 4
Explanation: The boy can buy ice cream bars at indices 0,1,2,4 for a total price of 1 + 3 + 2 + 1 = 7.

Solution

/**
 * @param {number[]} costs
 * @param {number} coins
 * @return {number}
 */
var maxIceCream = function (costs, coins) {
  //Declare result var
  let bars = 0;

  //Sort costs array
  costs.sort((a, b) => a - b);

  //FOR loop to compare coins with cost
  for (let i = 0; i < costs.length; i++) {
    //If coins is greater than or equal to cost, subtract cost from coins and increment bars
    if (coins >= costs[i]) {
      coins -= costs[i];
      bars++;
    }
  }
  //Return bars
  return bars;
};